TY - JOUR
T1 - Isomorphism of relative holomorphs and matrix similarity
AU - Gebhardt, Volker
AU - Hernandez Alvarado, Alberto J.
AU - Szechtman, Fernando
PY - 2024
Y1 - 2024
N2 - Let V be a finite dimensional vector space over the field with p elements, where p is a prime number. Given arbitrary α, β ∈ GL(V), we consider the semidirect products V ⋊ (α) and V ⋊ (β), and show that if V ⋊ (α) and V ⋊ (β) are isomorphic, then α must be similar to a power of β that generates the same subgroup as β; that is, if H and K are cyclic subgroups of GL(V) such that V ⋊ H ≈ V ⋊ K, then H and K must be conjugate subgroups of GL(V). If we remove the cyclic condition, there exist examples of nonisomorphic, let alone nonconjugate, subgroups H and K of GL(V) such that V ⋊ H ≈ V ⋊ K. Even if we require that noncyclic subgroups H and K of GL(V) be abelian, we may still have V ⋊ H ≈ V ⋊ K with H and K nonconjugate in GL(V), but in this case, H and K must at least be isomorphic. If we replace V by a free module U over Z/pmZ of finite rank, with m > 1, it may happen that U ⋊ H ≈ U ⋊ K for nonconjugate cyclic subgroups of GL(U). If we completely abandon our requirements on V, a sufficient criterion is given for a finite group G to admit nonconjugate cyclic subgroups H and K of Aut(G) such that G ⋊ H ≈ G ⋊ K. This criterion is satisfied by many groups.
AB - Let V be a finite dimensional vector space over the field with p elements, where p is a prime number. Given arbitrary α, β ∈ GL(V), we consider the semidirect products V ⋊ (α) and V ⋊ (β), and show that if V ⋊ (α) and V ⋊ (β) are isomorphic, then α must be similar to a power of β that generates the same subgroup as β; that is, if H and K are cyclic subgroups of GL(V) such that V ⋊ H ≈ V ⋊ K, then H and K must be conjugate subgroups of GL(V). If we remove the cyclic condition, there exist examples of nonisomorphic, let alone nonconjugate, subgroups H and K of GL(V) such that V ⋊ H ≈ V ⋊ K. Even if we require that noncyclic subgroups H and K of GL(V) be abelian, we may still have V ⋊ H ≈ V ⋊ K with H and K nonconjugate in GL(V), but in this case, H and K must at least be isomorphic. If we replace V by a free module U over Z/pmZ of finite rank, with m > 1, it may happen that U ⋊ H ≈ U ⋊ K for nonconjugate cyclic subgroups of GL(U). If we completely abandon our requirements on V, a sufficient criterion is given for a finite group G to admit nonconjugate cyclic subgroups H and K of Aut(G) such that G ⋊ H ≈ G ⋊ K. This criterion is satisfied by many groups.
KW - matrix similarity
KW - relative holomorph
KW - semidirect product
UR - http://www.scopus.com/inward/record.url?scp=85205298570&partnerID=8YFLogxK
UR - https://ezproxy.uws.edu.au/login?url=https://doi.org/10.1017/S0004972724000546
U2 - 10.1017/S0004972724000546
DO - 10.1017/S0004972724000546
M3 - Article
AN - SCOPUS:85205298570
SN - 0004-9727
JO - Bulletin of the Australian Mathematical Society
JF - Bulletin of the Australian Mathematical Society
ER -